How to Create a Simple Email Sending Software Using C# Windows Forms

By: Unknown on 16:14

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This is an SMTP (Simple Mail Transfer Protocol) client based application. This project describes an approach to sending email message from your desktop computer to webmail with or without attachment.

In order to implement SMTP client, I am using two namespaces as given below. In addition to sending message from local computer, I am using “smtp.gmail.com” as a host server and 587 as host server port no.

To create this software first go to your IDE (Integrated Development Environment) Visual Studio then select C# and go to Windows Forms Application.

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Net;
using System.Net.Mail;

namespace Email_Sanding_Softwares
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void label2_Click(object sender, EventArgs e)
        {

        }

    private void button2_Click(object sender, EventArgs e)
    {
        try
        {
            SmtpClient client = new SmtpClient("smtp.gmail.com");
            client.Port = 587;
            client.EnableSsl = true;
            client.Timeout = 100000;
            client.DeliveryMethod = SmtpDeliveryMethod.Network;
            client.UseDefaultCredentials = false;
            client.Credentials = new NetworkCredential(
              "yourid@gmail.com", "yourgmailpassword");
            MailMessage msg = new MailMessage();
            msg.To.Add(textBox_To.Text);
            msg.From = new MailAddress("yourid@gmail.com");
            msg.Subject = textBox_Subject.Text;
            msg.Body = textBox_Message.Text;
            Attachment data = new Attachment(textBox_Attachment.Text);
            msg.Attachments.Add(data);
            client.Send(msg);
            MessageBox.Show("Successfully Sent Message.");
        }
        catch (Exception ex)
        {
            MessageBox.Show(ex.Message);
        }
    }

    private void button_Upload_Click(object sender, EventArgs e)
    {
        OpenFileDialog dlg = new OpenFileDialog();
        if (dlg.ShowDialog() == DialogResult.OK)
        {
            textBox_Attachment.Text = dlg.FileName.ToString();
        }
    }
    }
}